Hello, I am new to electrical systems so bare with me. I have a 1955.2 Chevy truck with a new GM crate motor, modern alternator, an Accel 52000 breakerless ignition distributor and an Accel 8140 coil canister. I have a modern "universal" wiring harness. This truck used to have a 305 with a points distributor so the wiring had a ballast resistor. I am now updating this and am confused on the wiring. Below is a link to a diagram I drew so you can see how it is currently wired. I am hoping you all can double check everything and let me know if something seems incorrect. But most importantly I think the distributor is not hooked up correctly. The orange wire is labeled "coil +" this wire used to go to the ballast resistor. A friend said that this now goes to the distributor (the Accel manual says hook to a "switched 12 volt source"). The manual also says to delete the ballast resistor and run a wire from the coil + to the starter solenoid, which I did. On another forum one person said that I need to run an additional wire from the coil + to the orange wire on the distributor and splice it in, but there was no mention of this in the manual. Does that sound right? http://rides.webshots.com/photo/2816928660102726664REjUia?vhost=rides&vhost=rides Thanks for any help you can provide. Michael
The Jalopy Journal
